Can someone modify these codes , instead of showing the output str8 away , it actually shows the step by step on how to get it . Something like this. I need it step by step from generating hamming code to error detection and then error correction. Below the image are codes in python

option=int(input('Press 1 for generating hamming code Press 2 for finding error in hamming code \t Enter your choice:-- '))

if(option==1): # GENERATE HAMMING CODE print('Please enter a maximum of 8 data bits') d=input() data=list(d) data.reverse() c,ch,j,r,h=0,0,0,0,[]

while ((len(d)+r+1)>(pow(2,r))): r=r+1

for i in range(0,(r+len(data))): p=(2**c)

if(p==(i+1)): h.append(0) c=c+1

else: h.append(int(data[j])) j=j+1

for parity in range(0,(len(h))): ph=(2**ch) if(ph==(parity+1)): startIndex=ph-1 i=startIndex toXor=[]

while(i

for z in range(1,len(toXor)): h[startIndex]=h[startIndex]^toXor[z] ch+=1

h.reverse() print('Hamming code generated would be:- ', end="") print(int(''.join(map(str, h))))

elif(option==2): # DETECT ERROR IN RECEIVED HAMMING CODE print('Enter the hamming code received') d=input() data=list(d) data.reverse() c,ch,j,r,error,h,parity_list,h_copy=0,0,0,0,0,[],[],[]

for k in range(0,len(data)): p=(2**c) h.append(int(data[k])) h_copy.append(data[k]) if(p==(k+1)): c=c+1 for parity in range(0,(len(h))): ph=(2**ch) if(ph==(parity+1)):

startIndex=ph-1 i=startIndex toXor=[]

while(i

for z in range(1,len(toXor)): h[startIndex]=h[startIndex]^toXor[z] parity_list.append(h[parity]) ch+=1 parity_list.reverse() error=sum(int(parity_list) * (2 ** i) for i, parity_list in enumerate(parity_list[::-1])) if((error)==0): print('There is no error in the hamming code received')

elif((error)>=len(h_copy)): print('Error cannot be detected')

else: print('Error is in',error,'bit')

if(h_copy[error-1]=='0'): h_copy[error-1]='1'

elif(h_copy[error-1]=='1'): h_copy[error-1]='0' print('After correction hamming code is:- ') h_copy.reverse() print(int(''.join(map(str, h_copy))))

else: print('Option entered does not exist')

Question 2: Given an 8 bits data store in main memory as 01001100. Compute the Hamming code that for this data. Show the computation of each check bit clearly in your steps of calculation using the table below. Position12 11 9 8 76 5 4 3 2 Position number Data bit C1 (--1) C2 (1-) C4 (-1-) C8 (1 H. Code Question 2: Given an 8 bits data store in main memory as 01001100. Compute the Hamming code that for this data. Show the computation of each check bit clearly in your steps of calculation using the table below. Position12 11 9 8 76 5 4 3 2 Position number Data bit C1 (--1) C2 (1-) C4 (-1-) C8 (1 H. Code