Can you help me answer the question by using my material that shows on pictures? Can you show the calculation for finding the answer?

156-1 exercise I:the burger baron Claude Forbes is a regional manager of The Burger Baron restaurant chain, The Baron would like to open a franchise in Sappington. Two properties are up for sale, and Claude wants to choose the location that has the most traffic. 156-2 exercise 1 :the burger baron On 54 randomly selected days over a six- month period, an average of 92 cars passed by location A during the lunch hour, from noon to 1PM. On 62 randomly selected days, 101 cars passed by location B during the lunch hour. The standard deviations for the two locations were 16 and 23, respectively. Significance Level Null Hypothesis Alternative Hypothesis Location A Location B Sample Size (n) 54 62 Sample Mean (x 92 cars 101 cars Sample Std. Dev. (s) 16 cars 23 cars 156-3 exercise 1 :the burger baron Question Is the difference between the amount of traffic at locations A and B statistically significant at the 0.01 level? A. Yes. B. ONo. Significance Level 0.0 Null Hypothesis Alternative Hypothesis Location A Location B Sample Size (n) 54 Sample Mean (x) 92 cars 101 cars Sample Std. Dev. (s 16 cars 23 cars 156-4 exercise 1 :the burger baron First you set up the hypotheses The null hypothesis states that there is no difference in mean traffic flow during the lunch hour at the two locations. Since you are only interested in whether the traffic is different at the two locations, you conduct a two-sided hypothesis test. Significance Level 0.01 Null Hypothesis HA = HI Alternative Hypothesis Location A Location B Sample Size (n) 54 62 Sample Mean (x 92 cars 101 cars Sample Std. Dev. (s) 16 cars 23 cars 156-5 exercise1:the burger baron Next, you find the z-value for the difference between the two sample means using the appropriate formula. The z-value is -2.47 Z = ( X , - X . ) - ( H , - H . ) (92 - 101 ) - (0)156-5 exercisel : the burger baron Next, you find the z-value for the difference between the two sample means using the appropriate formula. The z-value is -2.47 Z = - ( X , . X . ) - ( 1 , - U . ) (92 - 101 ) - (0) = -2.47 16 + 23 Significance Level 0.01 Null Hypothesis HA = H Alternative Hypothesis HA # HB Location A Location B Sample Size (n) 62 Sample Mean (x) 92 cars 101 cars Sample Std. Dev. (s) 16 cars 23 cars 156-6 exercisel :the burger baron A z-value of -2.47 corresponds to a left-tail probability of 0.0068. Since you are doing a two-sided test, you must double this probability to find the correct p-value: 0.0136. Significance Level 0.01 Null Hypothesis HA = P Alternative Hypothesis HA # UB Location A Location B Sample Size (n) 54 62 Sample Mean (x) 2 cars 101 cars Sample Std. Dev. ($) 16 cars 23 cars p-value = 0.0136 0.0068 0.0068 -2.47 +2.47 156-7 exercisel :the burger baron The p-value is higher than the significance level. You cannot reject the null hypothesis. On the basis of these data, Claude has insufficient evidence to show that one location has more traffic than the other. Significance Level 2.01 Null Hypothesis Alternative Hypothesis Sample Size On ISUEHOUSE EVIDENCE" HE Location B 54 62 Sample Mean (X) 92 cars 101 cars Sample Std. Dev. (s) 16 cars 23 cars 0.0136 > 0.01 p-value > significance level p-value = 0.0136 0.0068 0.0068 -2.47 +2.47