Can you help me print this display in a near aligned colum format, the rest of the code is written but I cant seem to get this right

#include "library.h$"$

#include

#include

void display$($const College a$[],$ unsigned n$)\{$

std::cout $<<$ std::left $<<$ std::setw$(30)<<$ "Name" $<<$ std::setw$(10)<<$ "Cost" $<<$ std::setw$(15)<<$ "Acceptance Rate" $<<$ std::endl;

for $($unsigned i $=0$; i $<$ n; i$++)\{$

std::cout $<<$ std::left $<<$ std::setw$(30)<<$ a$[$i$].$name $<<$ std::setw$(10)<<"$$$"<<$ a$[$i$].$cost $<<$ std::setw$(15)$;

std::cout $<<$ std::fixed $<<$ std::setprecision$(2)<<$ a$[$i$].$acceptance$\_$rate $<<"\%"<<$ std::endl;

$\}$

double total$\_$cost $=0$;

for $($unsigned i $=0$; i $<$ n; i$++)\{$

total$\_$cost $+=$ a$[$i$].$cost;

$\}$

double average$\_$cost $=$ total$\_$cost $/$ n;

std::cout $<<$ "Average cost: $$"<<$ std::fixed $<<$ std::setprecision$(2)<<$ average$\_$cost $<<$ std::endl;

$\}$

int search$($const College a$[],$ unsigned n$,$ std::string name, std::string category$)\{$

for $($unsigned i $=0$; i $<$ n; i$++)\{$

if $($category $==$ "name" && a$[$i$].$name $==$ name$)\{$

return i;

$\}$

$\}$

return $-1$;

$\}$

void sort$\_$by$\_$name$($College a$[],$ unsigned n$)\{$

for $($unsigned i $=0$; i $<$ n $-1$; i$++)\{$

for $($unsigned j $=0$; j $<$ n $-$ i $-1$; j$++)\{$

if $($a$[$j$].$name $>$ a$[$j $+1].$name$)\{$

College temp $=$ a$[$j$]$;

a$[$j$]=$ a$[$j $+1]$;

a$[$j $+1]=$ temp;

$\}$

$\}$

$\}$

$\}$

void sort$\_$by$\_$cost$($College a$[],$ unsigned n$)\{$

for $($unsigned i $=0$; i $<$ n $-1$; i$++)\{$

for $($unsigned j $=0$; j $<$ n $-$ i $-1$; j$++)\{$

if $($a$[$j$].$cost $>$ a$[$j $+1].$cost$)\{$

College temp $=$ a$[$j$]$;

a$[$j$]=$ a$[$j $+1]$;

a$[$j $+1]=$ temp;

$\}$

$\}$

$\}$

$\}$

void sort$\_$by$\_$acceptance$($College a$[],$ unsigned n$)\{$

for $($unsigned i $=0$; i $<$ n $-1$; i$++)\{$

for $($unsigned j $=0$; j $<$ n $-$ i $-1$; j$++)\{$

if $($a$[$j$].$acceptance$\_$rate $>$ a$[$j $+1].$acceptance$\_$rate$)\{$

College temp $=$ a$[$j$]$;

a$[$j$]=$ a$[$j $+1]$;

a$[$j $+1]=$ temp;

$\}$

$\}$

$\}$

$\}$