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can you please show the work of the multiplication in details? Thank you The rate constant of a chemical reaction at 25C has been found
can you please show the work of the multiplication in details? Thank you
The rate constant of a chemical reaction at 25C has been found to be 3.5102s1. What is the rate constant at 77C, and the frequency factor? Given that the activation energy =50.2kJmol1, and the universal gas constant =8.314Jmol1K1. k1=3.5102s1T1=25C=25+273=298KEa=50.2kJmol1k2=??s1T2=77C=77+273=350KR=8.314Jmol1K1lnk1k2=REa(T11T21)ln3.5102s1k2=8.314Jmol1K150.2103Jmol1(298K1350K1)lnk2=0.34k2=e0.34=1.4s1 Step by Step Solution
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Essentials Of Chemical Reaction Engineering
Authors: H. Scott Fogler
1st Edition
0137146124, 978-0137146123
