Can you provide me a simple pseudocode for the following question based on Java?

Question:

The Apriori algorithm for discovering frequent itemsets can be expensive. So people are always looking at different ways to improve further the approach's efficiency.

One expensive step, for example, is validating candidate itemsets by counting their supports to find the ones meeting or exceeding the support threshold. A common implementation is to use a hash$-$tree. If this step is done na$$vely$,$ the implementation will be too slow to be used.

Let us consider an Apriori program that takes as input the frequent itemsets of length k $($with respect to some support$-$count threshold$),$ the transaction itemsets, and a support$-$count threshold, and produces as output the frequent itemsets of length k$+1.($We assume the support$-$count threshold for the input frequent itemsets provided will be the same as$,$ or lower than, the requested threshold for the output.$)$ Let us name such a program levelUp.

How much time levelUp will take for a given task depends on how many pre$-$candidates are produced $($by the join step$).$ A pre$-$candidate advances to being a candidate itemset if it passes the apriori test. At a given support$-$count threshold, the same number of candidate itemsets will result, regardless. But perhaps we can reduce the number of pre$-$candidates produced.

Consider that we order the items in each itemset from least to most frequent, rather than just ordering them in some $$random$$ way, say lexicographically $($as by the standard algorithm$).$ That is$,$ how frequently each item appears in the transaction database; so the frequencies of those $1-$itemsets. Why could this help? The prefixes of the frequent itemsets of length k will be less common, meaning fewer pre$-$candidates should result from the join step. If this is significant in practice, this could make the algorithm perform better.

Write a program in Python $(3)$ or in Java called $$levelUp$.$py$$ or $$LevelUp$.$java$,$ respectively, to test this. Your algorithm should take three arguments, and a fourth optional argument:

a file with the frequent itemsets of length k at the given support threshold $($but not with the support counts reported$),$

a file with the transaction itemsets, and

the support threshold count.

E$.$g$.,$

$\%$ python levelUp.py mushroom$-$lev$4-$sup$500.$dat mushroom$-$trans.dat $500$

or

$\%$ java LevelUp mushroom$-$lev$4-$sup$500.$dat mushroom$-$trans.dat $500$

The frequent itemsets are to be read in from a file; e$.$g$.,$ mushroom$-$lev$4-$sup$500.$dat.

Each frequent itemset is on a separate line and is space separated.

Each item is represented by an integer value.

For each itemset, the items are ordered in the same way.

E$.$g$.,$

$1571113$

$37112329$

This should run the usual Apriori algorithm to write to standard output the frequent itemsets of length k$+1,$ as described in A$.$ above, with the support counts.

If called with the optional argument, e$.$g$.,$

$\%$ python levelUp.py mushroom$-$lev$5-$sup$500.$dat mushroom$-$trans.dat $500$ mushroom$-$lev$1-$sup$500-$wCount.dat

it should do the same, but applying the pre$-$candidate optimization, of ordering the items per itemset by frequency. The last argument, e$.$g$.,$ mushroom$-$lev$1-$sup$500-$wCount.dat, is a file of the frequent $1-$itemsets with the support counts. The $$wCount$$ variant for a frequent$-$itemset file is the same as above, except

The first integer per line is the support count.

E$.$g$.,$

$3811571113$

$23737112329$

Instrument your program to track running time, the number of pre$-$candidates found, and the number of candidates found.

Test at least on an input of level $5$ and a support$-$count threshold of $500$ from the mushroom transaction database.