CHEM $112$ Lab: Review of Chem $111$ Lab

$2.$ Calculate the amount in grams of the solute required to make $25\mathrm{.}0mL$ of a $0\mathrm{.}15-M$ solution of each of the following:

a$.N{a}_{3}P{O}_4$

$])$:$\}$

$[\frac{0-16\mathrm{.}004}{163\mathrm{.}94}$

b$.N{a}_{2}C{O}_3$

$Na-22\mathrm{.}992$

$C-12\mathrm{.}011$

$\frac{0-16\mathrm{.}003}{105\mathrm{.}99}$

$mo{l}_{N{a}_2}C{O}_3=\mathrm{.}025L_{\text{s}\text{o}\text{l}\text{u}\text{t}\text{e}}\mathrm{.}15=\mathrm{.}00375$mol

$\mathrm{.}00375mo{l}_{N{a}_{2}C{O}_3}\frac{105\mathrm{.}99}{1MOINaN{a}_3}=\mathrm{.}397gN{a}_{2}C{O}_3$