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Class Management | Help Week5 Begin Date: 6/26/2023 12:01:00 AM -- Due Date: 7/11/2023 11:59:00 PM End Date: 8/10/2023 11:59:00 PM (8%) Problem 2: Two

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Class Management | Help Week5 Begin Date: 6/26/2023 12:01:00 AM -- Due Date: 7/11/2023 11:59:00 PM End Date: 8/10/2023 11:59:00 PM (8%) Problem 2: Two blocks are connected by a massless rope. The rope passes over an ideal (frictionless and massless) pulley such that one block with mass my = 12.5 kg is on a horizontal table and the other block with mass my = 7.5 kg hangs vertically. Both blocks experience gravity and the tension force, T. Use the coordinate system specified in the diagram. m m, Otheexpertta.com ed 25% Part (a) Assuming friction forces are negligible, write an expression, using only the variables provided, for the acceleration that the block of mass my ted experiences in the x-direction. Your answer should involve the tension, T. ted a1= T/m1 Correct! ted * 25% Part (b) Under the same assumptions, write an expression for the acceleration, d2, the block of mass my experiences in the y-direction. Your answer should be in terms of the tension, T and m2- leted Grade Summary leted a2 = m2 ( g - P ) | Deductions 0% Potential 100% leted B () 7 8 9 HOME Submissions Attempts remaining: 987 pleted C g 1 4 5 6 (0% per attempt) pleted h 1 2 3 detailed view 0% ial k m 2 P 0 0% npleted VO BACKSPACE DEL CLEAR mpleted 0% Submit Hint I give up! Hints: 1 for a 0% deduction. Hints remaining: 2 Feedback: 1 for a 0% deduction 5 RClass Management | Help Week5 Begin Date: 6/26/2023 12:01:00 AM -- Due Date: 7/11/2023 11:59:00 PM End Date: 8/10/2023 11:59:00 PM (4%) Problem 7: Referring to the image to the right, the mass of Block 1 is mi = 3.47 kg while the mass of Block 2 is m2 - 9.33 kg. The coefficient of kinetic friction between Block 1 and the inclined surface is / = 0.37. The inclined surface is at an angle 0 = 37.2 above the horizontal. 2 50% Part (a) Using the variables from the problem statement together with the acceleration due to gravity, g, write an equation for the magnitude of the acceleration of the system. Hint: Based upon the numeric choices, Block 1 will accelerate up the incline while the suspended block, Block 2, accelerates vertically downward. a = g (m2 - m1 My cos(0) - m1 sin(0) )/( m1 + m2 ) 25% Part (a) Assuming the blocks are stuck together, what is the maximum magnitude of acceleration amax of the blocks in terms of the variables in the problem statement? amax = UM g Grade Summary Deductions 0% Potential 100% B ( 7 8 9 HOME Submissions a c 4 5 6 Attempts remaining: 993 D g h 1 2 (0% per attempt) detailed view M 0 END 0% 0% n P VO BACKSPACE DEL CLEAR 0% 0% Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback 25% Part (b) Calculate a value for the magnitude of the maximum acceleration amax of the blocks in m/s-. amax = 1.960 X Attempts Remain 25% Part (c) Write an equation for the largest spring constant kmax for which the upper block does not slip. Kmax = 4 Mug/M X Attempts Remain 25% Part (d) Calculate a value for the largest spring constant kmax for which the upper block does not slip, in N/m. Kmax = 88.85 - Correct All content @ 2023 Expert TA, LLC 6Class Management | Help Week5 Begin Date: 6/26/2023 12:01:00 AM -- Due Date: 7/11/2023 11:59:00 PM End Date: 8/10/2023 11:59:00 PM (10%) Problem 14: A book with mass m = 3.25 kg rests on the surface of a table. The coefficient of static friction between the book and the table is us = 0.75 and the coefficient of kinetic friction is uk = 0.28. F.m m H s , H K Otheexpertta.com ted eted 25% Part (a) Write an expression for Fm the minimum force required to produce movement of the book on the surface of the table. eted Fm = M, mg / Correct! eted leted 25% Part (b) Solve numerically for the magnitude of the force Fm in Newtons. Fm = 23.89 / Correct! leted leted 25% Part (c) Write an expression for a, the book's acceleration, after it begins moving. (Assume the minimum force, Fm, continues to be applied.) leted a = (Hs m - Uk m )/m Grade Summary Deductions 0% Potential 100% pleted a B Hk ( ) 7 8 9 HOME Submissions oleted Hs 1 1 4 5 6 Attempts remaining: 996 (0% per attempt) d g h 1 2 3 detailed view pleted + 10% END pleted 10% m P VO BACKSPACE DEL CLEAR 10% Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 3 Feedback: 0% deduction per feedback. 25% Part (d) Solve numerically for the acceleration, a in m/s. a = 4.610 Correct! All content @ 2023 Expert TA, LLC

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