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COEFFICIENT OF STATIC FRICTION (Answer only analysis data/Question) Weight - mass xq mass in kg For each mass given or table, the corresponding weight is
COEFFICIENT OF STATIC FRICTION
(Answer only analysis data/Question)
Weight - mass xq mass in kg For each mass given or table, the corresponding weight is calculated as below. - Weight of Carrier Weight of Pan Plus / Weight of pant Trial Plus Loadis ( N) Load/s' (N ) Weight of caliset W1 = m xg = mx10 | W 2 = mxg = mxlol = 1. (36, 2 x10 ) X10= 0.362 / (16.0*10 )X10= 0.16/ 0. 442 2 , ( 5 2. 0 * 10 ) X10 = 0.52 ( 19.4 X10 ) X10 = 0.194 0. 373 3 . ( 67 . 7 X 1 0 ) X 10 = 0. 677 ( 23. 5 x 10 ) X10 = 0.235 0.347 4. ( 84.0X10 ) X10 = 0.84 1( 27.3 * 10 ) *10 = 0.273 0. 325 UA) Average Coefficient of Static Friction | 0. 3718Trial RISE" AB " RUN" AC RISE ( cm ) ( cm ) RUN 8.0 17.0 0.4706 2 24.3 21.5 1. 1302 Average Coelf"of static, fril 0. 8004 Ilaverage - llAt UB - 0.3718 + 0.8004 2 2 - 0. 5861 Percent Difference - IllA - RIB/ X 100 elaverage 10.3718 - 0,80 04 X 100 0. 5861 - 73.1% elaverage Percent Differ 0.3718 0.8004 0.5861 73.1%Set-up B The distance from A to C is B the 'run' and the distance from A to B is the 'rise' A C rise = run\fSet-up A Wooden cart In the set-up the wooden cart is the carrier and the one hanging on the other end of the pulley is the pan. Pulley system weight of the pan ULA = weight of the carrierStep by Step Solution
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