Compounding interest if $3,500 is invested at a rate of 6.23% per year, compounded continuously, find the value of the investment after the given number of years.

G(t)=-3t+1
H(t)=2t+5
Find (g h)(t)

F(n)-n3+2
G(n)=-4n+4
Find (2f+g)(n)

F(t)=t-5
G(t)=-t2+5
Find (4f+4g)(t)

F(x)=-x+3
G(x)=3x-3
Find (4t-4g)(x)