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Consider a 24-bit floating point type that has 1 sign bit, 6 exponent bits, and 17 mantissa bits. Other than that, it encodes just as
Consider a 24-bit floating point type that has 1 sign bit, 6 exponent bits, and 17 mantissa bits. Other than that, it encodes just as a IEEE 754 number does. What is the maximum (finite) value that this type can hold? You can leave your answer in formulaic form. Also, what is its (big-Endian) representation for that value? As a hint, if there are e bits in the exponent, then the exponent offset is (2e/2) 1 = 2^(e1) 1
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Consider a 24-bit floating point type that has 1 sign bit, 6 exponent bits, and 17 mantissa bits. Other than that, it encodes just as a IEEE 754 number does. What is the maximum (finite) value that this type can hold? You can leave your answer in formulaic form. Also, what is it's (big-Endian) representation for that value? As a hint, if there are e bits in the exponent, then the exponent offset is 2 1= 2e-1 -1Step by Step Solution
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