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Consider a homogeneous hemispherical shell (hollow bowl) with mass and radius , as shown in the figure on the left. (a) In the configuration in

Consider a homogeneous hemispherical shell (hollow bowl) with mass image text in transcribed and radius image text in transcribed, as shown in the figure on the left.

image text in transcribed

(a) In the configuration in the figure on the left, obtain the position of the center of mass image text in transcribed of the hemispherical shell taking the origin at the point image text in transcribed.

(b) Get the moments of inertia of the hemispherical shell image text in transcribed for rotations around axes parallel to the image text in transcribed direction that pass through the origin image text in transcribed, through the center of mass image text in transcribed and by the pole image text in transcribed. Pay attention when applying the parallel axes theorem.

(c) As illustrated in the figure on the right, consider a physical pendulum composed of a hemispherical shell with a flat circular edge facing downwards and set to oscillate around a fixed point image text in transcribed, located at a distance above its pole image text in transcribed. The rigid rod that connect the points image text in transcribed and image text in transcribed has negligible mass and remains always perpendicular to the spherical shell at its pole image text in transcribed. From the conservation of mechanical energy or the resulting torque (in relation to image text in transcribed) acting on the system, obtain the equation differential satisfied by the angle image text in transcribed which describes the position of the pendulum's center of mass in the presence of the constant gravitational field image text in transcribed . Note that the movement of the center of mass occurs along a single plane, perpendicular to the image text in transcribed direction. What is the frequency image text in transcribed of small oscillations of the system around the vertical equilibrium position image text in transcribed ?

12 Ay bi , M R = (X,Y,Z) 0 = (0, 0, 0) G 1.14.1. -2 G= CM = R P = (0, 0, -a 0 = arccos(R) w=0 12 Ay bi , M R = (X,Y,Z) 0 = (0, 0, 0) G 1.14.1. -2 G= CM = R P = (0, 0, -a 0 = arccos(R) w=0

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