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Consider inserting six keys 4 , 3 , 3 7 , 1 , 1 2 , 2 6 into an empty hash table of length

Consider inserting six keys 4,3,37,1,12,26 into an empty hash table of length m =11using open addressing with the hash function hi(k)= k mod 11. Illustrate the steps of insertingthe keys above. Show all your calculations.1) Using linear probing - H(k, i)=(hi(k)+ i) mod 11 where i =0,1,2,..., m-12) Using double hashing with h2(k)-1+(k mod 9) or H(k, i)=(hi (k)+ i* h2(k)) mod 11where i -0,1,2,..., m-1Note: You must show all your calculations to receive the full credit.

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