Consider the data path below for a single cycle 32-bits MIPS processor Assume that we are executing the following instruction Sto 48(501) What is the value of the element pointed by arrow number 1 by in hexadecimal? Note that the PC and the content of registers Sto and St1 are found in bottom left of the figure below Data Memory Address Content Add Ox000016EC Ox0000ABOD ALU Add result Ox000016FO OxO0A01245 Shift left 2 Ox000016F4 Ox00001A42 Instruction (31-26) Control Res Branch IN Memo ATOO M ALUSE Hege Ox000171C OXOO0B124F Ox0001720 Ox00021345 Instruction 25-21) Read Read register PC Plead datat Ox0001724 Ox000067AB Instruction (2016) Read register ALU ALU Read Add data Test M instruction (15-111x Read data Write magister KEE Ox0001734 Instruction memory Ox0000AB35 Write det Data Register Wite memory Ox0001738 Ox0000FA72 16 2 ution 15-03 Sin AL erlend Ox0001740 Ox0000ABOC Register File and PC $t0 = 0x000016FO Control More TALVO MemW ALUS Regwrite Ox000171C Ox000B124F Instruction (25-21) Read address PC Read register 1 Ox0001720 Ox00021345 Instruction [20-16) Read data 1 Read register 2 Ox0001724 Ox000067AB Zero Instruction (31-0 Instruction memory Read ALU ALU Instruction (15-11] Write register data 2 Address Read data resu Ox0001734 Ox0000AB35 Write data Registers Data Write memory 0x0001738 Ox0000FA72 data Instruction (150) 16 32 Sign extend Ox0001740 Ox0000ABOC ALU control Register File and PC $t0 = 0x000016F0 Instruction [50] $t1 = Ox000016F4 1 PC = Ox000014BAO (Before executing LW) Instruction 15-01 Select one: O0002DE4 O b. 0000001724 Ox00002DEO d. 0x00001654 E O 00001720