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consider the following algorithm that implements selection sort: public static void selectionSort(Comparable[] a){ int N= a.lenght; for( int i=0; i

consider the following algorithm that implements selection sort:

public static void selectionSort(Comparable[] a){

int N= a.lenght;

for( int i=0; i

int min=i;

for(int j=i+1;j

if(less(a[j], a[min])) min=j;

exch(a,i,min);}

}

if you are choosing a cost metric(i.e what operation should be counted), in order to determine this algorithm's Big-Oh order, what operation would be the best choice?

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