Consider the following pseudocode. 1. procedure main() a: integer := 1 b: integer := 2 procedure middle ) b: integer := a procedure inner() print a, b a : integer := 3 -- body of middle inner() print a, b -- body of main middle ) 14. print a, b print a, 13. Suppose this was code for a language with the declaration-order rules of C (but with nested subroutines)--that is, names must be declared before use, and the scope of a name extends from its declaration through the end of the block. At each print statement, indicate which declarations of a and b are in the referencing environment. What does the program print (or will the compiler identify static semantic errors)? Repeat the exercise for the declaration-order rules of C# (names must be declared before use, but the scope of a name is the entire block in which it is declared) and of Modula-3 (names can be declared in any order, and their scope is the entire block in which they are declared). (Hint: each of the three languages will produce different output; one of the languages will produce an error.) Consider the following pseudocode. 1. procedure main() a: integer := 1 b: integer := 2 procedure middle ) b: integer := a procedure inner() print a, b a : integer := 3 -- body of middle inner() print a, b -- body of main middle ) 14. print a, b print a, 13. Suppose this was code for a language with the declaration-order rules of C (but with nested subroutines)--that is, names must be declared before use, and the scope of a name extends from its declaration through the end of the block. At each print statement, indicate which declarations of a and b are in the referencing environment. What does the program print (or will the compiler identify static semantic errors)? Repeat the exercise for the declaration-order rules of C# (names must be declared before use, but the scope of a name is the entire block in which it is declared) and of Modula-3 (names can be declared in any order, and their scope is the entire block in which they are declared). (Hint: each of the three languages will produce different output; one of the languages will produce an error.)