Question
Consider the following reaction: O 2 (g) + 2 NO(g) 2 NO 2 (g) (a) The rate law for this reaction is first order in
Consider the following reaction: O2(g) + 2 NO(g) 2 NO2(g) (a) The rate law for this reaction is first order in O2(g) and second order in NO(g). What is the rate law for this reaction?
Rate = k [O2(g)] [NO(g)]
Rate = k [O2(g)]2 [NO(g)]
Rate = k [O2(g)] [NO(g)]2
Rate = k [O2(g)]2 [NO(g)]2
Rate = k [O2(g)] [NO(g)]3
Rate = k [O2(g)]4 [NO(g)] (b) If the rate constant for this reaction at a certain temperature is 11900, what is the reaction rate when [O2(g)] = 0.0218M and [NO(g)] = 0.0297 M? Rate = M/s. (c) What is the reaction rate when the concentration of O2(g) is doubled, to 0.0436 M while the concentration of NO(g) is 0.0297 M? Rate = M/s
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