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Consider the second order constant coefficient linear differential equation with initial values y '' ? 3y ' + 2y = e 3t , y(0) =

Consider the second order constant coefficient linear differential equation with initial values y'' ? 3y' + 2y = e3t , y(0) = 0, y' (0) = 3 .

(a) Find the characteristic polynomial q(s), then find the set Bq.

(b) The Bq in Part (1) should contain two functions. Denote these two functions by y1 and y2. Use variation of parameters to find a particular solution yp toy'' ? 3y' + 2y = e3t .

(c) Now the solution to the initial value problem is of the form yp + c1y1 + c2y2 for some undetermined constants c1, c2 ? R. Use the initial values to determine c1 and c2.

(d) From another point of view, y satisfies a system of first order linear differential equations. (question continues in picture)

image text in transcribedimage text in transcribed
y1 equations. More precisely, let y1 = y, y2 = y' and y = (starting from this part, y2 y1 and y2 have different meaning from Part (a), (b) and (c)). Then we have y1 = y2 0 y(0) = yo = (1) 32 = -291 + 3y2 + eat 3 write the above system in the vector form y' = Ay + f by finding A and f.\f

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