Consider the topology shown in Figure $4\mathrm{.}20.$ Denote the three subnets with

hosts $($starting clockwise at $12$:$00)$ as Networks A$,$ B$,$ and C$.$ Denote the

subnets without hosts as Networks D$,$ E$,$ and F$.$

a$.$ Assign network addresses to each of these six subnets, with the following

constraints: All addresses must be allocated from $214\mathrm{.}97\mathrm{.}254/23$; Subnet A

should have enough addresses to support $250$ interfaces; Subnet B should

have enough addresses to support $120$ interfaces; and Subnet C should

have enough addresses to support $120$ interfaces. Of course, subnets D$,$ E

and F should each be able to support two interfaces. For each subnet, the

assignment should take the form a$.$b$.$c$.$d$/$x or a$.$b$.$c$.$d$/$x $$ e$.$f$.$g$.$h$/$y$.$

b$.$ Using your answer to part $($a$),$ provide the forwarding tables $($using longest

prefix matching$)$ for each of the three routers.