Construct the 98% confidence interval for the difference P -P2 when x = 50, n =95, x2 =25, and n = 75. Round the answer to at least three decimal places. A 98% confidence interval for the difference between the two proportions is Construct the 99.9% confidence interval for the difference p -P2 when x = 60, n = 85, x2 = 73, n2 = 161. Round the answer to at least three decimal places. A 99.9% confidence interval for the difference between the two proportions is Traffic accidents: Traffic engineers compared rates of traffic accidents at intersections with raised medians with rates at intersections with two-way left-turn lanes. They found that out of 4640 accidents at intersections with raised medians, 2114 were rear-end accidents, and out of 4573 accidents at two-way left-turn lanes, 2029 were rear-end accidents. Part: 0/2 Part 1 of 2 (a) Assuming these to be random samples of accidents from the two types of intersection, construct a 99.8% confidence interval for the difference between the proportions of accidents that are of the rear-end type at the two types of intersection. Let p denote the proportion of accidents of the rear-end type at intersections with raised medians. Use tables to find the critical value and round the answer to at least three decimal places. A 99.8% confidence interval for the difference between the proportions of accidents that are < P1 - P2 of the rear-end type at the two types of intersection is Pain after surgery: In a random sample of 43 patients undergoing a standard surgical procedure, 24 required medication for postoperative pain. In a random sample of 99 patients undergoing a new procedure, only 19 required pain medication. Part: 0/2 Part 1 of 2 (a) Construct a 99.8% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. Let p denote the proportion of patients who had the old procedure needing pain medication. Use tables to find the critical value and round the answer to at least three decimal places. A 99.8% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures is Pretzels: In order to judge the effectiveness of an advertising campaign for a certain brand of pretzel, a company obtained a simple random sample of 99 convenience store receipts the week before the ad campaign began, and found that 27 of them showed a purchase of the pretzels. Another simple random sample of 79 receipts was taken the week after the ad campaign, and 42 of them showed a pretzel purchase. Part: 0 / 2 Part 1 of 2 (a) Construct a 99.8% confidence interval for the difference between the proportions of customers purchasing pretzels before and after the ad campaign. Let p denote the proportion of customers purchasing pretzels before the ad campaign. Use tables to find the critical value and round the answer to at least three decimal places. A 99.8% confident that the difference between the proportions of customers purchasing pretzels before and after the ad campaign is < P1 - P2 Defective electronics: A team of designers was given the task of reducing the defect rate in the manufacture of a certain printed circuit board. The team decided to reconfigure the cooling system. A total of 971 boards were produced the week before the reconfiguration was implemented, and 259 of these were defective. A total of 860 boards were produced the week after reconfiguration, and 168 of these were defective. Part: 0 / 2 Part 1 of 2 (a) Construct a 99.8% confidence interval for the decrease in the defective rate after the reconfiguration. Use tables to find the critical value and round the answer to at least three decimal places. A 99.8% confidence interval for the decrease in the defective rate after the reconfiguration is Cancer prevention: Colonoscopy is a medical procedure that is designed to find and remove precancerous lesions in the colon before they become cancerous. In a sample of 51,649 people without colorectal cancer, 6049 had previously had a colonoscopy, and in a sample of 8795 people diagnosed with colorectal cancer, 977 had previously had a colonoscopy. Part: 0 / 2 Part 1 of 2 (a) Construct a 90% confidence interval for the difference in the proportions of people who had colonoscopies between those who were diagnosed with colorectal cancer and those who were not. Let p denote the proportion of people without colorectal cancer who had colonoscopies. Use tables to find the critical value and round the answer to at least three decimal places. A 90% confidence interval for the difference in the proportions of people who had colonoscopies between those who were diagnosed with colorectal cancer and those who were not is