Could someone confirm if my data is correct ? Thank you !

4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 212 23 24 25 26 wo ww le I JOHNSON LEVEL & TOOL MFG. CO. INC. OL 19 S 4 3 21 8ths Ray Diagram for Part ( 9 ) : Of = 20 0m 1 = 360m 300 mm toomm do = 200 mm di = 120 mm *= 360 MM IMAGE 420 mm * = 200 mm OBJECT Af-loommOne lens with focal length, f = 100mm do, mm di, mm ho hi Mn Experiment 19 mm 17.78 mm 0.9357 mm - 0.60 mm 200 mm 120 mm Calculations 0.005 mm 0.008 mm 0.052 mm 0.056 mm 0.1088 mm 0.013 mm Ray diagram 300 mm -450 mm 100 mm 420 mm 22.1 mm 2.25 m Changing do di, mm ho hi Mn Ma do, mm Measured Calculated Measured Measured Calculated 1.05 mm -1.28 mm 140 mm 180 mm 350 mm 19 mm 20 mm -2.2 mm 100 mm 220 mm Infinity 19mm 33mm 1.74 mm 70 mm 250 mm 233.33 mm 19mm 37 mm 1.95 mm -3.57 mm 40 mm 280 mm 66.66 mm 19mm 38 mm 2 mm -7 mm 225 mm 0.78 mm 180 mm 140 mm 19mm 14 mm 0.74 mmReport for Experiment Phyll-04: Image Formation by Thin-Lens SystemThe object distance, focal length and image distance for a thin lens are related by thin lens equation. (2) The magnification of the image, M, is M -ni d; h d.fi do do - f = di =- do f 2 (5) do - f2 Equation 5 allows us to find the final image distance value for the two-lens system. The orientation and size of the final image can be found as follows: The total magnification produced by a lens system is equal to the product of the magnifications produced by each lens individually. Using Equation 3, we find that the first lens produces the magnification M = -". Similarly, the second lens causes the magnification M' = - di . The totalThe object distance, focal length and image distance for a thin lens are related by thin lens equation. (2) do The magnification of the image, M, is h; M = iwise IveauI vi lage 1 10 givevy ure writes uququvu. d. do - fi do f z (5) f 2 do - f 2 Equation 5 allows us to find the final image distance value for the two-lens system. The orientation and size of the final image can be found as follows: The total magnification produced by a lens system is equal to the product of the magnifications produced by each lens individually. Using Equation 3, we find that the first lens produces the magnification M = -. Similarly, the second lens causes the magnification M' = -1. The total d.magnication of the system, then, is m = MM ', showing that the nal image is inverted if m0, and changed in size by a factor of as compared with the original object. This value must be in agreement with the results obtained in experiment where the magnication can be found from formulae: M = I'lll, M' = IllH, m = MM' and h0' = hi. 0 0' 'Calculated value Experimental valuel = - 100% Calculated value