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(d) The untreated wastewater comprises 10g/L methanol (CH3OH) and 1.5g/L acetate (CH3COO). Using the half reactions below, estimate the total theoretical COD (COD' in g/L

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(d) The untreated wastewater comprises 10g/L methanol (CH3OH) and 1.5g/L acetate (CH3COO). Using the half reactions below, estimate the total theoretical COD (COD' in g/L ) of the wastewater given that the equivalent weight of oxygen is 8g/ e'eq. [6] Methanol: Acetate: 61CO2+H++e=61CH3OH+61H2O81CO2+81HCO3+H++e=81CH3COO+83H2O

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