Dear Expert tutor, please assist me for below multiple choise question for my statistic quiz,

note : please expalanation with clearly and don't writting with scratches because I will save this as for my study document

2" 3109's" If the average number of customers per day is 50 people and the standard deviation is 25 people, while the average customer service time is 20 minutes and the standard deviation is 10 minutes, then: The variation in the diversity of customer number data is greater than the variation in service time data. The variation in the diversity of customer number data is smaller than the variation in service time data. Variation in customer number data varies equal to variation in service time data CV number of customers 10% If the defective product that is generated from the factory has a chance of p :02 and follows the binomial distribution. The chances of getting a small defective product from 5 samples, namely: a. P(x24)-0.0067 b. c. d If there are many visitors to a bank every minute in the morning 3 people. When following the distribution of 393m the opportunity at one time to receive visitors 2 people, namely: If the coin is thrown three times then the chance Mammy appearing the same face for the third time the throwing is : a. 1/8 b. X c. 3/8 d 2/8 which statement is the most correct? a. Histograms are used for categorical and continuous data variables b Bar chart for variable data category c. Histogram for comparison between variable data d Histograms and bar charts are no different. The police intend to limit speed by using speed trap cameras in 4 different locations (L1, L2, L3 and L4). Traps are operated not all the time, but each location is operated with 40%. 30%, 10% and 20% trap cameras respectively for L1, L2, L3 and L4. According to records a motorist exceeded the speed limit (got a fine) at each L1, L2, l3 and L4 locations by 0.2, 0.1, 0.5 and 0.2. What are the chances of being fined? a. 0.2 b. 0.3 c. 0.4 d. 0.5 If f(x)=1/2 x. for0 S x S 2, then: a, P(x>1.0)=0.25 b. P(X>1.0) =0.75 c. P(x>1.0)=0.15 d. P(x>1.0)=0.55 Electricity a. Probability of getting a damage machine 5 years, if it is known that the energy source comes from diesel = 0.80 Correct formula for calculating probability P( AUBUC) = P(A) + P (B) +P(C) - (P(AUB) + P(AUC) + P(BUC)) P(AanC) P(A) + P (B) +P(C) - (P(AUB) + P(AUC) + P(BUC)) + P(AanC) P(A) + P (B) +P(C) - (P(AUB) + P(AUC) + P(BUC)) - P(AnC) P(A) + P (B) +P(C) (P(AUB) + P(AUC) + P(BUC)) P(AnB) ago-9i 10. If the number of engines is damaged every day and the many costs of repairing the engine, as well as the mm of damaged engine events based on previous factory experience as follows: : Number of damage machines (units) 0 1 2 3 4 mum 0.05 0.3 04 0.15 0.10 a. 0.40 b. 0.75 c. 0.65 d. Other