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def remove3big(list1, N): final_list = [] list1.sort() for i in range(0, N): max1 = 0 for j in range(len(list1)): if list1[j] > max1: max1 =
def remove3big(list1, N): final_list = [] list1.sort() for i in range(0, N): max1 = 0 for j in range(len(list1)): if list1[j] > max1: max1 = list1[j]; final_list.append(max1) list1 = [i for i in list1 if i not in final_list] print(list1) list1 = [1,2,3,4,5,6,6,5,4,3,2,1] N =3 remove3big(list1,3) 3. The list L contains arbitrary numbers. Write a Prolog program remove3big(L,R) that returns the reduced list R which contains those elements of list L that are different from three largest values in L. In other words, it is necessary to eliminate all duplicates of the three largest values in L and the remaining elements should be stored in R. You can use all Prolog functions. Example: ?- remove3big([1,2,3,4,5,6,6,5,4,3,2,1), R). R = [1, 1, 2, 2, 3, 3]
def remove3big(list1, N):
final_list = []
list1.sort()
for i in range(0, N):
max1 = 0
for j in range(len(list1)):
if list1[j] > max1:
max1 = list1[j];
final_list.append(max1)
list1 = [i for i in list1 if i not in final_list]
print(list1)
list1 = [1,2,3,4,5,6,6,5,4,3,2,1]
N =3
remove3big(list1,3)
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