Design a circuit in tinkercad, which simulates two players in the game of rock paper or scissors

using dip switches, and with three LEDs they will show the winner, or tie, ALSO ADD THE LOGIC DIAGRAM OF THE GAME

Design a spock lizard rock paper scissors GAME combinatorial circuit IN TINKERCAD:

Stone vs paper The paper wins, because the paper surrounds the stone

Stone vs lizard The stone wins, because the stone hits the lizard

Stone vs Spock $.$Spock wins, as Spock vaporizes the stone

Paper vs lizard $.$Lizard wins, because the lizard eats the paper

Paper vs Spock $.$Paper wins, because Paper disapproves of Spock

Lizard vs Spock $.$The lizard wins, because the lizard poisons Spock.

To alleviate this situation, we propose to encode both the inputs and outputs of the

following way. The input options will be represented with two boolean variables like

shown in the following table:

Representation Option

Stone $00$

Paper $01$

Lizard $10$

Spock $11$

As you will notice, using $4$ options requires $2$ bits for its representation. Having $3$

options, it would leave us with an unused combination, which would result in having some inputs

incorrect or illegal. The same would happen with $5$ or more options, which would also require bits

additional.

On the other hand, the result of the game would be that player $1$ wins $($which we will represent as

$00),$ that player $2$ wins $($which we will represent as $11)$ and that there is a tie $($which

we will represent as $01).$ You may find the encoding of the result strange. In fact,

other coding such as: Player $1$ wins coded as $10,$ player $2$ wins coded as

$01$ and tie coded as $00($or as $11),$ might seem more intuitive. However, in the end

of the exercise you will notice that the coding: $00,11$ and $01($player $1$ wins, player $2$ wins, tie

respectively$)$ is more convenient.

To complete, I propose that you add a second combinatorial circuit that turns on a

led when player $1$ wins and another led for when player $2$ wins. The tie can be associated

to the case in which no LED lights up$.$

The problem includes not only the design of the two circuits, but it will be necessary to verify their

functioning.