Question
Design the simplest sum-of-products circuit that implements the function: f (x1, x2, x3) = m(3, 4, 6, 7). my answer: M A(X1) B(X2) C(X3) F
Design the simplest sum-of-products circuit that implements the function: f (x1, x2, x3) = m(3, 4, 6, 7).
my answer:
| M | A(X1) | B(X2) | C(X3) | F |
| 0 | 0 | 0 | 0 | 0 |
| 1 | 0 | 0 | 1 | 0 |
| 2 | 0 | 1 | 0 | 1 |
| 3 | 0 | 1 | 1 | 1 |
| 4 | 1 | 0 | 0 | 0 |
| 5 | 1 | 0 | 1 | 1 |
| 6 | 1 | 1 | 0 | 1 |
| 7 | 1 | 1 | 1 | 0 |
X1.X2.X3 + X1.X2.X3 + X1.X2.X3 + X1.X2.X3
X1X2(x3+x3) + x1(X2.X3+X2.X3) ----- X3+x3 = 1 I reached this step but couldn't continue .. can anyone help me with the correct answer?
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Database Programming With Visual Basic .NET
Authors: Carsten Thomsen
2nd Edition
1590590325, 978-1590590324
