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Determine the COP of a refrigerator that removes heat from the food compartment at a rate of 5180 kJ/h for each kW of power
Determine the COP of a refrigerator that removes heat from the food compartment at a rate of 5180 kJ/h for each kW of power it consumes. Also, determine the rate of heat rejection to the outside air. The COP of the refrigerator is The rate of heat rejection to the outside air is kJ/h.
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