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e i240, Fall 2018-Lab R2 R1 Rly: R3y R3y R3 B1 R1x R2x R4 In the four bar linkage shown above, R3 is the driver,

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e i240, Fall 2018-Lab R2 R1 Rly: R3y R3y R3 B1 R1x R2x R4 In the four bar linkage shown above, R3 is the driver, R1 is the tolloves R2 is the connector, and R4 is the frame, where R1-3.25, R2-3.76, R3.2.56 R4-4.15 Since the sum of the shortest and longeat links is less than the sum of the two remaining links, this linkage is a Grashoff rechanism. There are four possible Grashoff mechanisms depending on which link ie the shortest. When the shortest link is the driver, the mechanien is a crank-rocker, which is the case here. Write a MATLAB program as follows: 1) 3 vill go from 84 to 804 in steps of 1". 2) For each value of 03, call the function newton2 to calculate 82 and 0a . Use 75 and 30 as the initial guesses for and 2 . Plot the four bar linkage, pausing 015 sec between each orientation. Pause an additional 8 sec after the first orientation. choose the origin at the lower left corner. Plot R1, R2, R3 and R4 in blue, green, red and black. Use the pbaspect statement. The graph for the final orientat the one on the attached sheet

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