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EDUC 606 LEARNING ACTIVITY 3 INSTRUCTIONS This learning activity consists of a variety of problems from Chapters 13-15. Include a title page with your assignment

EDUC 606 LEARNING ACTIVITY 3 INSTRUCTIONS This learning activity consists of a variety of problems from Chapters 13-15. Include a title page with your assignment in current APA. Answers must be clearly labeled and appear in consecutive order. Submit your assignment (answers only) as a Word document. 1. Calculate the mean, median, mode, standard deviation, and range for the following sets of measurements: a. 9, 7, 6, 6, 2 6-6-6-1.939-7 b. 12, 10, 9, 8, 6-9-9-nm-2-6 c. 82, 82, 82, 82, 82-82-82-0-0 d. 12, 10, 9, 8, 6, 45-15-9.5-nm-13.540-39 2. Answer the following questions a. Why is the SD in (d) so large compared to the SD in (b)? SD in (d) is so large compared to the SD in (b) because of the value 45.The SD of numbers in (b) was 9,now we are adding a number which is very far from mean in (b)[Mean in (b) =9] so SD in (d) becomes very large for the new dataset. b. Why is the mean so much higher in (d) than in (b)? Mean is so much higher in (d) than in (b) because of the value 45.The original dataset had small values resulting in mean =9,now after adding a big number 45,the sum becomes large and as a result mean is so much higher in (d) as compared to (b). c. Why is the median relatively unaffected? Median is affected by central numbers.The number 45 is at the end of the data, so it doesn't affect the median much other than the fact that now there are 6 numbers, so new median is average of third and fourth numbers rather than being equal to middle ie the third number in the part (b). d. Which measure of central tendency best represents the set of scores in (d)? Standard deviation best represents the set of scores in (d) because it skyrockets from that of part (b) and thus compels us to see for a big change in (d). 3. Fill in the blanks with the appropriate raw scores, z-scores, T-scores, and percentile ranks. Note: the Mean = 50, SD = 5. Assuming that T = z*10 + 50 Raw 35 1.2*5+50 =56 -1.5*5+50 = 42.5 -0.99*5+50 = 45.05 z (35-50)/5 = -3 1.2 (35- 50) /10= -1.5 -0.99 T -3*10+ 50 =20 1.2*10+ 50 = 62 35 -0.99*10 + 50 = 40.1 %ile 0.03 88.49 6.68 16 EDUC 606 4. The Graduate Record Exam (GRE) has a combined verbal and quantitative mean of 1000 and a standard deviation of 200. Scores range from 200 to 1600 and are approximately normally distributed. For each of the following problems: (a) draw a rough sketch, darkening in the portion of the curve that relates to the answer, and 200 1000 1600 (b) indicate the percentage or score called for by the problem. Z score for score = 200 = (200-1000)/200 = -4. Z score for score = 1600 = (1600-1000)/200 = 3 a. What percentage of the persons who take the test score above 1300? Z score = (1300-1000)/200 = 1.5 P(z> 1.5) =1- P(z<= 1.5) = 1- 0.9332 = 0.0668 So 6.68% of persons who take the test score above 1300. b. What percentage score above 800? Z score =(800-1000)/200 = -1 P(z>-1) = 1-P(z<=-1) = 1- 0.1587 = 0.8413 So 84.13% of persons score above 800. c. What percentage score below 1200? Z score = (1200-1000)/200 = 1 P(z<=1) = 0.8413 So 84.13% of persons score below 1200 d. Above what score do 20% of the test-takers score? Let the score be s. z = (s-Mean)/(Standard Deviation) P(Z > z) = 0.2 So z= 0.84 s = 0.84*200 + 1000 = 1168 e. Above what score do 30% of the test-takers score? Let the score be s. z = (s-Mean)/(Standard Deviation) P(Z > z) = 0.3 So z= 0.52 s = 0.52*200 + 1000 = 1104 5. For the data presented below, answer the questions that follow. EDUC 606 Score on political Individual awareness test 1 24 2 16 3 11 4 9 5 8 6 14 7 17 8 19 9 21 10 25 11 18 12 13 13 11 14 6 15 9 16 12 a. Construct a scatterplot. Score on current events test 23 12 11 6 13 11 16 16 21 25 11 13 14 10 10 7 30 25 20 Score on Current 15 Events test 10 5 0 5 10 15 20 25 30 Score on political awareness test b. Draw a regression line through the data point that \"fits\" the data points reasonably well. EDUC 606 30 25 20 Score on Current 15 Events test 10 5 0 5 10 15 20 25 30 25 30 Score on political awareness test c. Enclose the data points with a ellipse. 30 25 20 Score on Current 15 Events test 10 5 0 5 10 15 20 Score on political awareness test d. Estimate the direction of the correlation. Score on current events test increase with increase in score on political awareness test.So the correlation is in positive direction. e. Estimate the strength of the correlation coefficient. Weak correlation appears for scurrent events score less than 15 and very strong correlation appears for scuurent events score greater than 15. f. Now, use only the data points associated with current event scores of 15 and lower and indicate the effects this has on the direction and strength of the correlation coefficient. Direction - not fixed. Extremely weak strength. g. Explain why this is the case. EDUC 606 There appears to be no direction of correlation for current events score less than 16 because sometimes current events score increases and sometimes it decreases with increase in political awareness score.Also there appears to nearly zero strength of correlation as scores on one test do not show any effect on scores on other test h. Explain in words what a non-truncated scatterplot means. Non truncated scatterplot means that all the given values of both the variables are considered to determine the strength and direction of correlation and hence the relationship between the two variables. i. Identify how likely it is that a causal relationship has been indicated. Correlation doesn't imply causation so it can't be said without proper data models whether there is causal relationship or not. Submit Learning Activity 2 by 11:59 p.m. (ET) on Sunday of Module/Week 5

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