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El cloro y el gas hidrgeno reaccionan para formar cloruro de hidrgeno, Cl2(g) + H2(g) --> 2HCl (g). Si una muestra de 48,5 l de
El cloro y el gas hidrgeno reaccionan para formar cloruro de hidrgeno, Cl2(g) + H2(g) --> 2HCl (g). Si una muestra de 48,5 l de cloro gaseoso se hizo reaccionar con un exceso de hidrgeno a 450 K y 1,20 atm, cuntos gramos de hidrgeno se crearon?
por favor muestre el trabajo, gracias!
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