Electrons are emitted from the surface of a metal when it's exposed to light. This is called the photoelectric effect. Each metal has a certain threshold frequency of light, below which nothing happens. Right at this threshold frequency, an electron is eminled. Above this frequency, the electron is emitted and the extra energy is transferred to the electron The equation for this phenomenon is KE=hw-hm where K E is the kinetic energy of the emited electron, h = 6.63 x 10 Josis Planck's constant, v is the frequency of the light, and 2 is the threshold frequency of the metal Also, since E = hy, the equation can also be written as KE=E- where is the energy of the light and on is the binding energy of the electron in the metal no no Here are some data collected on a sample of cesium exposed to various energies of light, Light energy Electron emitted? Electron KE (eV) (V) 2.12 2.13 2.14 yes 2.15 yes 0.01 2.16 yos 0.02 "Note that I eV (electron volt) - 1.60 x 10. 0 Part A What is the threshold frequency of cesium? Express your answer numerically in hertz. View Available Hints)