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Evaluate the function f(x) at the given numbers (correct to six decimal places). f(x)=(x^(2)-3x)/(x^(2)-x-6),x=3.5,3.1,3.05,3.01,3.005,3.001,2.9,2.95,2.99,2.995,2.999 f(3.5)= f(3.1)= f(3.05)= f(3.01)= f(3.005)=
Evaluate the function
f(x)
at the given numbers (correct to six decimal places).\
f(x)=(x^(2)-3x)/(x^(2)-x-6),x=3.5,3.1,3.05,3.01,3.005,3.001,2.9,2.95,2.99,2.995,2.999
\
f(3.5)=
\
f(3.1)=
\
f(3.05)=
\
f(3.01)=
\
f(3.005)=
\
f(3.001)=
\
f(2.9)=
\
f(2.95)=
\
f(2.99)=
\
f(2.995)=
\
f(2.999)=
\ Guess the value of the limit of
f(x)
as
x
approaches 3 , correct to six decimal places. (If an answer does not exist, enter DNE.)\
\\\\lim_(x->3)(x^(2)-3x)/(x^(2)-x-6)=
\ Need Help?
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