Extending the Investigation This series-parallel circuit is more complex. It has a resistor in series, and then the circuit splits into two resistors in parallel to one another. The circuit looks like this. 1. The top 2 resistors are in parallel. To calculate the equivalent resistance of the whole circuit, rst determine the equivalent resistance of these two parallel resistors. Show your work here. 2. To find the equivalent resistance of the entire circuit, use the answer from Question 14 as one resistor in series with the 20 Q resistor. Show your work here.3. Check your work by measuring the overall voltage and current and calculating the resistance. Show your work here. 1/R = 1/R1 + 1/R2 1/R = 1/R1 + 1/R2 + 1/R/3 1/R = 1/R1 + 1/R2 + 1/R3 + 1/R = 1/10 + 1/20 1/R = 1/10 + 1/20 + 1/30 1/R4 1/R = 2/20 + 1/20 1/R = 6/60 + 3/60 + 6/60 1/R = 1/10 + 1/20 + 1/30 + 1/40 1/R = 3/20 1/R = 15/60 = 1/4 1/R = 12/120 + 5/120 + 4/120 + R = 20/3 R =4 3/120 1/R = 24/120 = 1/5 R = 5