Fill in all _'s, and submit this worksheet for grading in Assignments Horizontal equations: (x-xo) = Vex t and vx = vx Vertical equations: y = yo + v0\" t + V2 a t2 and vy = v0y + a t Component equations: V0}, = v0 cosB v0), = V\" sine Range equation: R = (vnzlg) sin(29) Pythagoras equation for v0, v0 : , and angle equation 6 = tan' ' (Vm/Vm) l Mps://www.compadre.orgysletslmechanics/illustrationz 6. cf_m Open the simulation, and run Animation 2 This is a hall being tossed straight upwards, to rise from a height of 0, and then it falls back down to a height of 0. Thus, the initial Vertical Velocity is not Zero. We begin using equations having \"y\" in our calculations. These are y = y" + v\"_v t + 1/2. a t2 v3; = v0). + a t (straight up and down means equations involving in: are not needed) These equations use \"up\" as the positive direction, therefore gravity (being down) has a value ofa = g = -9.8 m/sz. 7 \"mm\" m. nu l/> Click on Animation 2 at the bottom, then click the run triangle. You will see the ball go up, then go down, and plots of y, vy, and a. La. Click on reset. The ball is at its starting height, here Yo = In. Click run. The ball rises then drops to its nal height, y = m. Partly hidden, but legible beneath the ball, we can read the overall time for the up-and-down motion. This is t = s. Symmetry has the time to go up = time to go down. Thus, tup = s, and t = s. down l.b. We can use the yequations above, to calculate the initial speed Va}, and maximum height \"yum". First, y is symmetric at t = 4 s, is this the max/min height (choose one), What is v\" at this time? vy = 7 m/s. I Now from the starting point, use vy = v0y + a tup to calculate initial speed VDY = m/s. We now use y = y0 + v\"y tup + 1/2 a tup" to calculate the max height at tup = 4 s, y = in. Click with your mouse on the upper, light-blue ball, and in yellow, you can approximately veri/ your max height calculation.L 1.c. \"Down trajectory half\". This last half accomplishes one thing-calculate its nal velocity down--using tum\" = 4 5. Its speed is zero when it begins its downward trajectory. Its initial height is y0 = nal height in the \"up\" part, its v\