Fill in the Boolean Algebra axiom or theorem $($e$.$g$.,1$a$,1$b$,2$a$,$ etc.$)$ for each step of the following Boolean algebra minimization.

$(x+y)(x+z)=+xz+xy+yz$

$(x+y)(x+z)=x+xz+xy+yz$

$(x+y)(x+z)=x(1+z+y)+yz$

$(x+y)(x+z)=x(1)+yz$

$(x+y)(x+z)=x+yz$