Fill in the missing blanks.

Everyday Exam pies: Terminal Speed of the Human Body Let's estimate the terminal 5 peed of the human body. We start with the previous equation: _ .' 2mg ll _ ll ("owl-- We need to know the mass. drag coefcient. density of air. and densityr of air near the Earth's surface at standard pressure and temperature. ,r. = 1.2 kgg'm". Drag coefcient and cross sectional area depend on body orientation. so let's assume a standard skydiving posture: flat. horizontal.with arms and legs spread. In this case the drag coefcient will likely be {14-13. A reasonable value would be 2; = 1E. To approximate the crosssectional area we can use the authors average width of m and height of 1.5 m for an area of A; :1}.sm x 1.5m : 11.4.5 11:.2 Inserting these values into our terminal speed equation we have: y__ l stenkgoratmrs'o 1' '1; l[1.2kgfm3]iii.45m3] Fill in the missing words = 51 mfs = JEMPH terminals? speed is reached when the drag of force becomes as large as the body's weight V so that the net force is . Atthat point the body is in dynamiov equilibrium so the speed v" can no longer be increasing. but instead must remain