Finally, convinced the safety committee that a person on the spinning ride at Camp Snoopy accelerates even though the ride moves at a constant speed The next step for the Committee is to determine the direction of the acceleration and thus the direction of the net force on a person so that they can complete their safety proposal Equipment apparatus that spins a horizontal platform, stopwatch, meterstick Warm up Make a drawing of the path of an object in circular motion at constant speed On that path, use a dot to represent the object's position at time t 1 Label this point as O, and draw a vector at O to represent the magnitude and direction of the object's velocity at time t 1 Draw another dot to represent the object's position at a later time t 2 , shortly after t 1 , and label this point P Draw a vector at P to show the magnitude and direction of the object's velocity at time t 2 Redraw the velocity vectors with the tail of one vector (point P) at the tail of the other vector (point O) Keep the same size and direction as in the previous drawing To find the acceleration of the object, that is interested in the change in velocity (v) The change vis the increment that must be added to the velocity at time t 1 so that the resultant velocity has the new direction after the elapsed time t t1t2 Add the change in velocity v to the drawing of the velocity vectors it should be a straight line connecting the heads of the vectors Recalling the relationship between change in velocity and acceleration, construct a vector that represents the direction and magnitude of the average acceleration between the pair of velocities Would the direction of the acceleration be different for very close points on the object's path Repeat steps 1 3 for two different neighboring positions on the object's circular path Is the direction of the acceleration for this pair of velocities the same, or different as before What can conclude (in general) about the direction of acceleration Prediction Determine the direction of the acceleration for an object rotating in a circle at a constant speed Explain the reasoning

The Answer is in the image, click to view ...

Answered step by step

Verified Expert Solution

Link Copied!

Question

1 Approved Answer

Posted on Jun 25, 2024

Finally, convinced the safety committee that a person on the spinning ride at Camp Snoopy accelerates even though the ride moves at a constant speed.

Finally, convinced the safety committee that a person on the spinning ride at Camp Snoopy accelerates even though the ride moves at a constant speed. The next step for the Committee is to determine the direction of the acceleration and thus the direction of the net force on a person so that they can complete their safety proposal.

Equipment: apparatus that spins a horizontal platform, stopwatch, meterstick.

Warm up

Make a drawing of the path of an object in circular motion at constant speed. On that path, use a dot to represent the object's position at time t₁. Label this point as O, and draw a vector at O to represent the magnitude and direction of the object's velocity at time t₁. Draw another dot to represent the object's position at a later time t₂, shortly after t₁, and label this point P. Draw a vector at P to show the magnitude and direction of the object's velocity at time t₂.
Redraw the velocity vectors with the tail of one vector (point P) at the tail of the other vector (point O). Keep the same size and direction as in the previous drawing. To find the acceleration of the object, that is interested in the change in velocity (v). The change vis the increment that must be added to the velocity at time t₁ so that the resultant velocity has the new direction after the elapsed time t=t1t2. Add the change in velocity v to the drawing of the velocity vectors; it should be a straight line connecting the heads of the vectors.
Recalling the relationship between change in velocity and acceleration, construct a vector that represents the direction and magnitude of the average acceleration between the pair of velocities. Would the direction of the acceleration be different for very close points on the object's path?
Repeat steps 1-3 for two different neighboring positions on the object's circular path. Is the direction of the acceleration for this pair of velocities the same, or different as before? What can conclude (in general) about the direction of acceleration?