Find a particular solution, $y_p,$ of the differential equation $y^{\text{'}\text{'}}+4y^{\text{'}}+4y=e^{2x}.$

$y_p=\frac{1}{4}{e}^{2x}$

$y_p=e^{2x}$

$y_p=\frac{1}{2}{x}^2{e}^{2x}$

$y_p=\frac{1}{16}{e}^{2x}$

$y_p=2x{e}^{2x}$