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Find the absolute extrema of the function f(t)=2cos(t) +sin(2t) on the interval [0,/2] using the Extreme Value Theorem and the following steps, 1. f(t)= 2.

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Find the absolute extrema of the function f(t)=2cos(t) +sin(2t) on the interval [0,/2] using the Extreme Value Theorem and the following steps, 1. f(t)= 2. The value of Os ts 1/2 which makes f'(t)=0 is, to= 3. Using the value of to found in step 2., determine f(to)= 4. Determine the function value at the specified endpoints, f(0) = F( IT / 2) = 5. Combining steps 3. and 4., and using the Extreme Value Theorem, we have that Absolute Maximum: Absolute Minimum

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