Find the area of the region enclosed between y = 4sin(:c) and y = 3 cos(:c) from m = 0 to a: = 0.577. Hint: Notice that this region consists of two parts. I: Find the exact area of the region that lies beneath the curve 3; = 1 sin($), 0 g a: 3 1r. 9'. Find the exact area of the region that lies beneath the curve y = 2 36-32(33), 0 S a: 3 7r/ 3. f. (1 point) Find the exact area of the region that lies under the curve given by y = 2513(3) _ 3111(233), 0