Find the error in the following solution for 5 3(2x 1) = 4(x 5) 6. 5 3(2x 1) = 4(x 5) 6. 2(2x 1) = 4(x 5) 6 4x 2 = 4x 20 6 4x 2 = 4x 14 4x 2 4x = 4x 14 4x 2 = 14 From step 1 to step 2, subtracting 5 3 is incorrect. From step 2 to step 3, the 4 should have also been distributed to the 6 on the right side. From step 3 to step 4, 20 6 is not 14. From step 4 to step 5, subtracting 4x from both sides is incorrect. From step 5 to step 6, 2 should be 2