Find the slope of the curve y = 11x at ( - 3,99). The slope of the curve y = 11x at ( - 3,99) is (Simplify your answer.)What is the rate of change of the area of a circle (A =TCI'2) with respect to the radius when the radius is r = 7? The area changes at a rate of D. 3 (Type an exact answer, using :It as needed.) \fFind the value of the derivative. dy if y = 1 - 4x2 4 dx Ix = -5 dy (Simplify your answer.) dx X= - 5The equation for free fall at the surface of some planet (3 in meters, t in seconds) is s = 6.96t2. How long does it take a rock falling from rest to reach a velocity of 20.6 m/s on this planet? It takes sec for a rock falling from rest to reach a velocity of 20.6 m/s. ; > (Round to he nearest tenth as needed.) \fdy Write the function in the form y = f(u) and u = 900. Then find a as a function of x. y: e- 22x Which of the following has the function in the form y = f(u) and u = g(x)? U C. A. y=e ,u= -22x C: B. y= -e\". u=22x \\\\ Date 2 : ) A = n 8 ? ( liver in Question ) dA - d ( # 8 2 ) - 7 d ( 8 2 ) do New by using ( un) = now do 7 2 8 27 New dA = 2 1 X 7 = 14 x = +4 x 22 = 44 do 827 The answer can be 44 so let it to as lyn 9. S = 2 cot (t ) - e-E New Is 2 8 ( coff ( ) ) - d let ) at at = 2 x ( - cose(? t ) - e- * d (t ) - 7- 2 coser ? t te - t New we can we cosecant = 1 + cot't ds - 2 ( 1 + cot2+) + e-t = -2 - 260 (2 + + e-t New from S= 2006 ( t ) - e - t =) e-t - 2 cott - s ds - - 2-20tt + 2cot ( t) - s atDate (14 ) / (2 ) sink 1 + cosx Let to = sink I twos ( # ) Now f () = t 2 Now du . . { to) By using d lull = nund flail = d ( + 2 ) = 2t ? - dt du 4 t' () = 2 t at New dt d 1. Sink It corn Now using d l 4 du V2 ( It cost ) am (Itcosm) (cosm) - sinu( of (1) + d (com) ) dru ( 1 twosx ) 2 #Date I - cost + cos2 2 - sing ( of (-sinx) ) ( 1 +cosh ) 2 losx + cost + sink ( 1 teos x ) 2 Losh +1 1x ( I t caru ) ? (1 + cost ) dx New putting the value to sink I tcosy and dt dv ( 1 + cork ) New Al(x) = 2 x sinx I teosre 2 Sinx ( 1 + cosx ) 2