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FL 0 5 5 . ) : CH 4 + 0 . 5 0 2 2 0 0 + 2 H 2 : ( 1

FL05
5.): CH4+0.502200+2H2: (1) CH4+01=CH201+H2(2)02+20222002(3) CH201+00200+01+O2+ H21)(1)(2)(3)2)(1)3)2.01.0x107m^2/s 1.0sl 4)2.0

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