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For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: POT (T in kelvins)

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For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: POT (T in kelvins) and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: 0.0029 T (2my in meters, T in kelvins) Assume an object is emitting blackbody radiation. If the Kelvin temperature of an object is doubled, the amount of radiant energy emitted each second is twice the original amount. O True O False

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