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For concreteness, let us say that we are looking for a DFA over the alphabet Sigma = { 0 , 1 } . Also,

For concreteness, let us say that we are looking for a DFA over the alphabet \Sigma ={0,1}. Also, let
L0={x in {0,1}| the number of 0s and 1s in x are unequal} and L1={0n1n | n in N \cup {0}}. Observe
that L0\cap L1=. Does there exist such a DFA which accepts every string in L1 and rejects every string in
L0? Prove your answe

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