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For each of the following code snippets, match it to the appropriate ( worst - case ) time or space complexity, as specified at the

For each of the following code snippets, match it to the appropriate (worst-case) time or space complexity, as specified at the top of the snippet.
You should assume that the size of the input array a is .
If you're unfamiliar with , you should consider looking at the Algorithms Analysis Primer in the Week 0 sub-module.
Note that declaring an array of length n is frequently a operation, as many languages (including many versions of Java) will initialize each entry of the new array to its default value. You may assume that it is for this problem.
Question 6 options:
Time complexity of
function(int[] a)
d = new ArrayDeque
for( i=0; i < a.length; i++)
d.add(0, a[i])
(Extra) space complexity (i.e. not including space of array a) of
function(int[] a)
d = new ArrayDeque
for( i=0; i < a.length; i++)
d.add(0, a[i])
Time complexity of
function(int[] a)
d = new ArrayDeque
for( i=0; i < a.length; i++)
d.add(i, a[i])
Time complexity of
function(int[] a)
int[] b = new int[a.length]
return a[0]
(Extra) space complexity (i.e. not including space of array a) of
function(int[] a)
return a[0]
(Extra) space complexity (i.e. not including space of array a) of
function(int[] a)
d = new ArrayDeque
for( i=0; i < a.length; i++)
d.add(d.size()/2, a[i])
Time complexity of
function(int[] a)
return a[0]
(Extra) space complexity (i.e. not including space of array a) of
function(int[] a)
int[] b = new int[a.length]
return a[0]
(Extra) space complexity (i.e. not including space of array a) of
function(int[] a)
d = new ArrayDeque
for( i=0; i < a.length; i++)
d.add(i, a[i])
Time complexity of
function(int[] a)
d = new ArrayDeque
for( i=0; i < a.length; i++)
d.add(d.size()/2, a[i])
1.
time
2.
space
3.
time
4.
space
5.
time
6.
space

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