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For problems 2-5, use the pumping lemma for context-free languages to prove that L is not a CFL 3. Ls = {ab: n=2} 4. L2

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For problems 2-5, use the pumping lemma for context-free languages to prove that L is not a CFL 3. Ls = {a"b": n=2"} 4. L2 = { a'b'c: nsj}. 5. L3 = {w: w e{a,b,c}* and na(w)

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