For the following gas$-$phase reaction, how is the rate of disappearance of $N_{2}O$ related to the rate of appearance of $N_2?$

$2N_{2}O(g)2N_2(g)+O_2(g)$

$-\frac{N_{2}O}{}t=\frac{N_2}{}t$

$-\frac{N_{2}O}{}t=\frac{N_2}{2}t$

$-\frac{N_{2}O}{2}t=\frac{N_2}{}t$

$-\frac{N_{2}O}{2}t=0\mathrm{.}5\frac{N_2}{}t$

$-\frac{N_{2}O}{}t=4\frac{N_2}{}t$