For the reaction 2() + 32() = 23() we have Ka = 36 at 400 K, in a 50L reactor two moles of 2 and 6 moles of 2 are placed at 400k. Calculate the final composition at equilibrium.

3.- Para la reaccin N2(g)+3H2(g)=2NH3(g) se tiene Ka=36 a 400K, en un reactor de 50L se colocan dos moles de N2 y 6 moles de H2 a 400k. Calcule la composicin final en el equilibrio