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for this exothermic reversible reaction with a variable coolant flow rate. A+B2C has the following parameter values for the base case: E=25kcal/molCPA=CPB=CPC=20cal/mol/KHRx=20kcal/molCPI=40cal/mol/Kk=molkgs0.004dm6@310KT0=330KKc=1000@303KTa=320Kmc=1,000g/sFa0=5mol/sCPc=18cal/g/KCT0=0.3mol/dm31=1Equimolarfeed.CAO=0.3mol/dm3. Determine the conversion
for this exothermic reversible reaction with a variable coolant flow rate. A+B2C has the following parameter values for the base case: E=25kcal/molCPA=CPB=CPC=20cal/mol/KHRx=20kcal/molCPI=40cal/mol/Kk=molkgs0.004dm6@310KT0=330KKc=1000@303KTa=320Kmc=1,000g/sFa0=5mol/sCPc=18cal/g/KCT0=0.3mol/dm31=1Equimolarfeed.CAO=0.3mol/dm3. Determine the conversion in a 5,000-kg fluidized CSTR where UA=500cal/sK with Ta= 320K and b=2kg/m3 Step by Step Solution
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Introduction To Chemical Engineering Thermodynamics
Authors: J. M. Smith, Hendrick C Van Ness, Michael Abbott, Hendrick Van Ness
6th Edition
0072402962, 978-0072402964
