For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. In a marketing survey, a random sample of1000supermarket shoppers revealed that276always stock up on an item when they find that item at a real bargain price.(a) Letprepresent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain.Find a point estimate forp. (Enter a number. Round your answer to four decimal places.) (b) Find a 95% confidence interval forp. (For each answer, enter a number. Round your answers to three decimal places.) lower limit upper limit Give a brief explanation of the meaning of the interval.We are 95% confident that the true proportion of shoppers who stock up on bargains falls within this interval.We are 95% confident that the true proportion of shoppers who stock up on bargains falls outside this interval. We are 5% confident that the true proportion of shoppers who stock up on bargains falls above this interval.We are 5% confident that the true proportion of shoppers who stock up on bargains falls within this interval. (c) As a news writer, how would you report the survey results on the percentage of supermarket shoppers who stock up on items when they find the item is a real bargain?

Report the margin of error.Report the confidence interval. Reportpalong with the margin of error.Reportp.

What is the margin of error based on a 95% confidence interval? (Enter a number. Round your answer to three decimal places.)